AQA GCSE Physics Density of Irregular Solids required practical. Combined & Triple Science.
Need to revise first? Study the illustrated Density practical.
A student wants to determine the density of the irregularly shaped stone, shown in Figure 1.
Plan a valid method to determine its density in kg/m³.
[6 marks]
Measure
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Place the dry stone on a balance and record its mass.
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Fill a Eureka can with water until it is perfectly level with spout opening.
Place an empty measuring cylinder beneath the spout.
Tie a thin thread around the stone and gently immerse it until it is fully submerged.
Water will be pouring out of the spout and into the measuring cylinder
Once all the stone is fully immersed and all the water has poured out into the measuring cylinder, read the water level in the measuring cylinder.
The displaced water is equal to the volume of the stone.
Calculate
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Convert volume from cm³ to m³
Convert mass from g to kg
Divide the mass in kilograms by the volume in cubic metres.
Density = mass ÷ volume
Exam Challenge
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Place the dry stone on a balance and record its mass.
Fill a Eureka can with water until it is perfectly level with spout opening.
Place an empty measuring cylinder beneath the spout.
Tie a thin thread around the stone and gently immerse it until it is fully submerged.
Water will be pouring out of the spout and into the measuring cylinder
Once all the stone is fully immersed and all the water has poured out into the measuring cylinder, read the water level in the measuring cylinder.
The displaced water is equal to the volume of the stone.
To calculate density:
Convert volume from cm³ to m³
Convert mass from g to kg
Divide the mass in kilograms by the volume in cubic metres.
Density = mass ÷ volume
Missed some steps? Return to this practical’s step-by-step visual explanation.
More Exam-style Questions
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100 cm = 1 m
1,000,000 cm³ = 1 m³
Divide the volume in cm³ by 1,000,000 to obtain volume in m³.
Then, you can calculate density by dividing mass in kg by volume in m³.
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The thin string.
A thick string would displace too much water, which makes the volume measurement an overestimation, as the displaced water would be a combination of the stone’s volume and the string’s volume. An overestimated volume, would lead to an underestimated density value.
A thin string would cause minimal discrepancy, so should be used instead.
Continue Revising Paper 1
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